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Amplitudes for the Exotic b1π Decay (view source)
Revision as of 14:30, 29 July 2011
, 14:30, 29 July 2011→NEW
<math>
<math>
C=\frac{1}{\sqrt{2}} \left[ C^{a,b} + (-1)^L C^{b,a} \right]
C(L)=\frac{1}{\sqrt{2}} \left[ C^{a,b} + (-1)^L C^{b,a} \right]
</math>
</math>
\left[ \sqrt{\frac{2L_X+1}{2J_X+1}}
\left[ \sqrt{\frac{2L_X+1}{2J_X+1}}
\left(\begin{array}{cc|c}
\left(\begin{array}{cc|c}
L_X & 1 & J \\
L_X & 1 & J_X \\
0 & \lambda_{b_1} & \lambda_{b_1}
0 & \lambda_{b_1} & \lambda_{b_1}
\end{array}\right)
\end{array}\right)
<math>
<math>
A^{J_X}=\sum_{\lambda_{b_1},\lambda_\omega,\lambda_\rho}
A^{J_X}=\sum_{\lambda_{b_1},\lambda_\omega,\lambda_\rho}
\langle \Omega_X 0 \lambda_{b_1} | U | J_X m_X \rangle C_X k^{L_X}
\langle \Omega_X 0 \lambda_{b_1} | U | J_X m_X \rangle C_X(L_X) k^{L_X}
\langle \Omega_{b_1} 0 \lambda_\omega | U | 1 , m_{b_1}=\lambda_{b_1} \rangle C_{b_1} q^{L_{b_1}}
\langle \Omega_{b_1} 0 \lambda_\omega | U | 1 , m_{b_1}=\lambda_{b_1} \rangle C_{b_1}(L_{b_1}) q^{L_{b_1}}
\langle \Omega_\omega 0 \lambda_\rho | U | 1 , m_\omega=\lambda_\omega \rangle C_\omega u^{L_\omega}
\langle \Omega_\omega 0 \lambda_\rho | U | 1 , m_\omega=\lambda_\omega \rangle C_\omega(L_\omega) u^{L_\omega}
\langle \Omega_\rho 0 \lambda_\rho | U | J_\rho , m_\rho=\lambda_\rho \rangle C_\rho v^{L_\rho}
\langle \Omega_\rho 0 \lambda_\rho | U | J_\rho , m_\rho=\lambda_\rho \rangle C_\rho(L_\rho) v^{L_\rho}
</math>
</math>