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| | We start off with Maxwell's Equation in the Lorentz gauge: | | We start off with Maxwell's Equation in the Lorentz gauge: |
| − | :<math>\square^2A^\mu(\mathbf{r},t) = \square^2A^\mu (r)=\mu j^\mu (r)</math><br><br> | + | :<math>\square^2A^\mu(\mathbf{r},t) = \square^2A^\mu (r)=\mu j^\mu (r)</math><br> |
| − | where we use the metric signature (+,+,+,-) and<br><br> | + | where we use the metric signature (+,+,+,-) and<br> |
| − | :<math>A^\mu = (\mathbf{A},\frac{\Phi} {c})</math>, | + | :<math>A^\mu = (\mathbf{A},\frac{\Phi} {c})</math> |
| | :<math>\square^2=\part_\mu \part^\mu = \nabla^2 - \frac{1}{c^2} \frac{\part^2}{\part t^2}</math> | | :<math>\square^2=\part_\mu \part^\mu = \nabla^2 - \frac{1}{c^2} \frac{\part^2}{\part t^2}</math> |
| − | :<math>j^\mu = (\mathbf{j},c\rho), \part_\mu= (\mathbf{\nabla}, \frac{1}{c} \frac{\part}{\part t})</math><br><br> | + | :<math>j^\mu = (\mathbf{j},c\rho), \part_\mu= (\mathbf{\nabla}, \frac{1}{c} \frac{\part}{\part t})</math><br> |
| − | Lorentz Gauge: <math>\part_\mu A^\mu = 0 \rArr \mathbf{\nabla} \cdot \mathbf{A}-\frac{1}{c^2} \frac{\part\Phi}{\part t}=0</math><br><br> | + | The gauge condition for the Lorentz gauge is |
| − | Introduce Green's function at<math> (\mathbf{r},t)=r \quad</math> from some impulse source at<math> r'=(\mathbf{r}',t') \quad</math><br><br> | + | :<math>\part_\mu A^\mu = 0 \rArr \mathbf{\nabla} \cdot \mathbf{A}-\frac{1}{c^2} \frac{\part\Phi}{\part t}=0</math><br> |
| | + | Introduce the Green's function at <math> (\mathbf{r},t)=r \quad</math> from some impulse source at<math> r'=(\mathbf{r}',t') \quad</math><br><br> |
| | <math>\square^2_rG(r,r')=\delta^4(r-r')</math><br><br> | | <math>\square^2_rG(r,r')=\delta^4(r-r')</math><br><br> |
| | Let <math> \tilde{G} (q) = \frac{1}{(2\pi)^2} \int d^4r e^{-iq\cdot r} G(r,0)</math><br><br> | | Let <math> \tilde{G} (q) = \frac{1}{(2\pi)^2} \int d^4r e^{-iq\cdot r} G(r,0)</math><br><br> |