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<math>\frac{d^4y}{dx^4}=-(\frac{\rho}{ET^2})\frac{d^2y}{dt^2}</math>
 
<math>\frac{d^4y}{dx^4}=-(\frac{\rho}{ET^2})\frac{d^2y}{dt^2}</math>
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Knowing that the motion of the beam will be oscillatory let's us assume that the solution can be divided into two parts, one representing the maximum amplitude of the motion and the other representing the periodic nature of the motion.
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Knowing that the motion of the beam will be oscillatory let's assume that the solution can be divided into two parts, one representing the maximum amplitude of the motion and the other representing the periodic nature of the motion.
    
<math>\frac{y(x,t)}{}=y_a(x)e^{i \omega t}</math>
 
<math>\frac{y(x,t)}{}=y_a(x)e^{i \omega t}</math>
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<math>y_n = \sum_m{c_{nm}f_m}</math>
 
<math>y_n = \sum_m{c_{nm}f_m}</math>
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We know that the solutions to the uniform case, as the eigenfunctions of a Hermitian matrix operation, are orthogonal. This means that taking the inner product of
    
[[Media:NonuniformAnalysisNew.pdf|Nonuniform-Width Analytical Model]]
 
[[Media:NonuniformAnalysisNew.pdf|Nonuniform-Width Analytical Model]]
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