*With a LinEngineering 1.8 Degree Motor and a radius of .5" for the pulley, the step size would be 0.005" or 0.127mm which is well within a 2mm scintillator. | *With a LinEngineering 1.8 Degree Motor and a radius of .5" for the pulley, the step size would be 0.005" or 0.127mm which is well within a 2mm scintillator. |