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Construction of a Tabletop Michelson Interferometer (view source)
Revision as of 19:46, 2 July 2009
, 19:46, 2 July 2009→Determining Angle of First Diffraction Minimum
<math>|\mathbf{r}-\mathbf{r}'|=\sqrt{(x-x')^2+(y-y')^2+z'^2}=\sqrt{r^2+r'^2+2r\rho^2cos\phi}</math><br><br>
<math>|\mathbf{r}-\mathbf{r}'|=\sqrt{(x-x')^2+(y-y')^2+z'^2}=\sqrt{r^2+r'^2+2r\rho^2cos\phi}</math><br><br>
<math>=r'-\frac{2r\rho'cos\phi}{2r'}, \frac{\rho'}{r'}=sin\theta'</math><br><br>
<math>=r'-\frac{2r\rho'cos\phi}{2r'}, \frac{\rho'}{r'}=sin\theta'</math><br><br>
<math>\frac{1}{|\mathbf{r}-\mathbf{r}'|} \approx \frac{1}{r'^2}\left(\frac{1+2rsin\theta'cos\phi}{r'}\right)</math>
<math>\frac{1}{|\mathbf{r}-\mathbf{r}'|} \approx \frac{1}{r'^2}\left(1+\frac{2rsin\theta'cos\phi}{r'}\right)</math>