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Construction of a Tabletop Michelson Interferometer (view source)
Revision as of 19:34, 2 July 2009
, 19:34, 2 July 2009→Determining Angle of First Diffraction Minimum
Let<math>\mathcal{J}(r')=\int_0^a rdr\int_0^2\pi d\phi \frac{e^{ik|\mathbf{r}-\mathbf{r}'|}}{|\mathbf{r}-\mathbf{r}'|}</math><br><br>
Let<math>\mathcal{J}(r')=\int_0^a rdr\int_0^2\pi d\phi \frac{e^{ik|\mathbf{r}-\mathbf{r}'|}}{|\mathbf{r}-\mathbf{r}'|}</math><br><br>
Then <math>A(r')=\frac{-z'\dot{A_0}}{2\pi c}e^{-ikct'}\mathcal{J}(r')</math>
Then <math>A(r')=\frac{-z'\dot{A_0}}{2\pi c}e^{-ikct'}\mathcal{J}(r')</math>
<math>|\mathbf{r}-\mathbf{r}'|=\sqrt{(x-x')^2+(y-y')^2+z'^2}=\sqrt{r^2+r'^2+2r\rho^2cos\phi}</math><br><br>
<math>=r'-\frac{2r\rho'cos\phi}{2r'}, \frac{\rho'}{r'}=sin\theta'</math>