196
edits
Changes
Jump to navigation
Jump to search
Line 26:
Line 26: + + +
Construction of a Tabletop Michelson Interferometer (view source)
Revision as of 15:56, 2 July 2009
, 15:56, 2 July 2009→Determining Angle for First Diffraction Minimum
Chose the "retarded" solution, such that the function is zero unless t>t'<br>
Chose the "retarded" solution, such that the function is zero unless t>t'<br>
<math>G(x,x')=\frac{1}{(2\pi)^4}\int d^3ke^{-i\mathbf{k}(x-x')}\int d(\frac{\omega}{c}) \frac{e^{i\omega(t-t')}}{(\frac{\omega}{c}-k)(\frac{\omega}{c}+k)}\Theta</math><br>
<math>G(x,x')=\frac{1}{(2\pi)^4}\int d^3ke^{-i\mathbf{k}(x-x')}\int d(\frac{\omega}{c}) \frac{e^{i\omega(t-t')}}{(\frac{\omega}{c}-k)(\frac{\omega}{c}+k)}\Theta</math><br>
<math>=\frac{1}{(2\pi)^4}\int d^3ke^{-i\mathbf{k}(x-x')}(2\pi i \frac{e^{ick(t-t')}-e^{-ick(t-t')}}{2k)})\Theta
</math>