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Target Diamond Structural Analysis (view source)
Revision as of 14:55, 23 April 2009
, 14:55, 23 April 2009→Interference
The propogating wave will not reflect back from the diamond coherently; it will instead form spherical wavelets. We must either account for these or find them insignificant.
The propogating wave will not reflect back from the diamond coherently; it will instead form spherical wavelets. We must either account for these or find them insignificant.
We can treat the diamond as a single-slit experiment. In this analysis, the slit will be represented by some finite slice of the diamond, which will then be the resolution size. We will call this resolution size R. The distance the light travels, from the diamond to the detector, is L. From this projection, we know that there will be a first intensity of zero at a distance <math>\frac{b}{2}</math>.
We can treat the diamond as a single-slit experiment. In this analysis, the slit will be represented by some finite slice of the diamond, which will then be the resolution size. We will call this resolution size R. The distance the light travels, from the diamond to the detector, is L. From this projection, we know that there will be a first intensity of zero at a distance <math>\frac{b}{2}</math> from the center of the screen. Basic trigonometry tells us that
<math>\theta = \tan^{-1} (\frac{R}{L})</math>
Because the irradiance, from the Fraunhofer approximation, is
<math>I(\theta) = I(0) \frac{\sin(\beta)}{\beta}^2 </math>
and <math>\beta</math> is defined as
<math>\beta = \frac{kR}{2}\sin(\theta)</math>
we can solve for I in terms of X.
<math> I(x)
== Color of the Laser ==
== Color of the Laser ==
* Compensate for interference
* Compensate for interference
* Compensate for other sources of error
* Compensate for other sources of error
* Calculate expected error
* Calculate expected error</math>