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This is not an easy equation to solve without using a Fourier transform. Therefore, we'll do just that, with G as the transformed function.
 
This is not an easy equation to solve without using a Fourier transform. Therefore, we'll do just that, with G as the transformed function.
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<math>G = \frac{1}{4\pi^2}\int{g(\Delta x,\Delta t)e^{-ik\Delta x}e^(i\omega\Delta t}d^3x dt}</math>
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<math>G = \frac{1}{4\pi^2} \int{g(\Delta x,\Delta t)e^{-ik\Delta x}e^{i\omega \Delta t}d^3x dt}</math>
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g = (copy)
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Therefore,
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We will then need to plug this function into the
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<math>g = \frac{1}{4\pi^2} \int{G(\Delta x,\Delta t)e^{-ik\Delta x}e^{i\omega \Delta t}d^3k d\omega}</math>
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earlier equation. We can change
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We will then need to plug this function into the earlier equation. To make this easier, we know that the four-dimensional delta function on the right-hand side can be simplified.
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(copy equals-right-hand-side delta-function from
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<math>\delta = \frac{1}{4\pi^2} \int{e^{-ik\Delta x}e^{i\omega \Delta t}d^3k d\omega}</math>
 
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notes)
      
Now, we have an equation with integrals on both  
 
Now, we have an equation with integrals on both  
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