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| Of course, thickness is not the only thing we need. After calculating <math> \tau </math> and uncovering the mirror, we will also detect the third laser reflection. We can calculate that the amplitude of this new combined wave will be | | Of course, thickness is not the only thing we need. After calculating <math> \tau </math> and uncovering the mirror, we will also detect the third laser reflection. We can calculate that the amplitude of this new combined wave will be |
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− | <math>A^2 _{123} = A^2 + C^2 _1 A^2 + C^2 _2 A^2 + 2 C _1 C _2 \cos ( d _2 - d _1 ) + 2 C _1 \cos ( - d _1 ) + 2 C _2 \cos ( - d _2 ) </math> | + | <math>A^2 _{123} = A^2 + C^2 _1 A^2 + C^2 _2 A^2 + 2 C _1 C _2 A^2 \cos ( d _2 - d _1 ) + 2 C _1 A^2 \cos ( - d _1 ) + 2 C _2 A^2 \cos ( - d _2 ) </math> |
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| Although this equation looks very complicated, we know that | | Although this equation looks very complicated, we know that |
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| Simplifying our initial equation, we find that | | Simplifying our initial equation, we find that |
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− | <math>A^2 _{123} = A^2 + C^2 _1 A^2 + C^2 _2 A^2 + 2 C _1 C _2 \cos ( 2 \tau / V _d ) + 2 C _1 \cos ( - 2 s / v _a ) + 2 C _2 \cos ( - 2 \tau / v _d - 2 s / v _a ) </math> | + | <math>A^2 _{123} / A^2 = 1 + C^2 _1 + C^2 _2 + 2 C _1 C _2 \cos ( 2 \tau / V _d ) + 2 C _1 \cos ( - 2 s / v _a ) + 2 C _2 \cos ( - 2 \tau / v _d - 2 s / v _a ) </math> |
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| Because the cosine is an even function, we can slightly simplify this further. | | Because the cosine is an even function, we can slightly simplify this further. |
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− | <math>A^2 _{123} = A^2 + C^2 _1 A^2 + C^2 _2 A^2 + 2 C _1 C _2 \cos ( 2 \tau / V _d ) + 2 C _1 \cos ( 2 s / v _a ) + 2 C _2 \cos ( 2 \tau / v _d + 2 s / v _a ) </math> | + | <math>A^2 _{123} / A^2 = 1 + C^2 _1 + C^2 _2 + 2 C _1 C _2 \cos ( 2 \tau / V _d ) + 2 C _1 \cos ( 2 s / v _a ) + 2 C _2 \cos ( 2 \tau / v _d + 2 s / v _a ) </math> |
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| This equation, athough complicated, is completely solvable, as the only unknown is the s-term. | | This equation, athough complicated, is completely solvable, as the only unknown is the s-term. |